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If y=1/(x(x+1))then what is y3?...

If `y=1/(x(x+1))`then what is `y_3`?

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`y=1/(x(x+1))=1/x-1/(x+1)rArry_1=(-1)/x^2+1/((x+1))^2y_2=2/x^3-2/((x+1))^4thereforey_3=(-6)/x^4+6/((x+1))^4`
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MBD PUBLICATION-THREE DIMENSIONAL GEOMETRY-QUESTION BANK
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