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Show that f(x)=x^3-6x^2+24x+4 has neithe...

Show that `f(x)=x^3-6x^2+24x+4` has neither a maximum nor a minimum value.

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`f(x)=x^3-6x^2+24+4=f(x)=3x^2-12x+24=3(x^2-4x+8)=3((x-2)^2+4)` as `f(x)ne`0 for all `x in R` the function has neither a local maximum nor local minum. But has a absolute minimum 12 at x =2.
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