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If intx/((x-1)(2x-1))=int[A/(x-1)+B/(2x-...

If `intx/((x-1)(2x-1))=int[A/(x-1)+B/(2x-1)]dx` find A and B.

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`int(xdx)/((x-1)(2x-1))=int[1/(x-1)+1/(2x-1)]dxA=B=1`
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