At a certain temperature and total pressure of `10^5` Pa ,iodine vapour contains `40%` by volume of iodine atoms. Calaulate `K_p` for the equilibrium, `1_2(g)iff2I(g)`.

Explanation

Percentage by volume of gaseous iodine atoms=`40%`
`therefore` Mole fraction of gaseous iodine atome =`40/100`
`therefore` Partial pressure of gaseous iodine atome= `40/100xx10^5Pa=0.4xx10^5Pa`
Partial pressure of gaseous `I_2=0.6xx10^5 Pa`
`therefore K_p=P_I^2/P_(I_2)=(0.4xx10^5)^2/(0.6xx10^5)=2.67xx10^4Pa`