The degree of ionisation of 0.1 M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the pKa of bromoacetic acid.

Explanation

`K_a=calpha^2=0.1xx0.132xx0.132=1.74xx10^-3`
`therefore pKa=-logK_a=-log(1.74xx10^-3)=3-0.2405=2.76`
`[H^+]=calpha=0.1xx0.132=1.32xx10^-2M`
`therefore pH=-log(1.32xx10^-2)=2-0.1205=1.88`