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An organic compound contains 69% carbon ...

An organic compound contains `69%` carbon and `4.8%` hydrogen and the remaining is oxygen. Calculate the mass of `CO_2` and `H_2O` formed when 0.20 g of the compound is subjected to combustion?

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The correct Answer is:
`69=(12)/44xx(x)/0.2xx100: x("mass of" CO_2) = 0.0506 g`
`4.8=(2)/18xx(y)/0.2xx100=; y`(mass of `H_2O`) = 0.086 g
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