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If the normals drawn at the points `t_(1)` and `t_(2)` on the parabola meet the parabola again at its point `t_(3)`, then `t_(1)t_(2)` equals.

A

2

B

`-1`

C

`-2`

D

`t_(3)-(2)/(t_(3))`

Text Solution

Verified by Experts

The correct Answer is:
A
Let normal at t meets the parabola again at `t_(3)`
`:.t_(3)= -t-(2)/(t) " " :.t^(2)+t_(3)*t+2=0`
`t_(1)&t_(2)` are the roots of the equation
`:.t_(1)t_(2)=2 `
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