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f(x) = {{:(xsinx " if " 0 ltx le(pi)/(2)...

`f(x) = {{:(xsinx " if " 0 ltx le(pi)/(2)),((pi)/(2)sin(pi + x )" if " (pi)/(2) lt x lt pi):}` then f(x) is discontinuous at

A

`(pi)/(4)`

B

`(pi)/(2)`

C

`(2pi)/(3)`

D

`(3pi)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
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