Is the following situation possible? If so, determine their present ages. The sum of the ages of two friends is 20 years.
Four years ago, the product of their ages in years was 48.

Represent the following situations in the form of quadratic equations : Rohan's mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan's present age.

A father's age is three times the sum of the ages of his two children. After 5 years his age will be 2 times the sum of their ages. Find the present age of the father.

If 2 is added to numerator and denoinator to a fraction, it becomes 9/10 . If 3 is subtracted from numerator and denominator , the fraction becomes 4/5 . Find the fraction. OR A girl is twice as old as her sister. Four years, hence the product of their ages ( in years) will be 160. Find their present ages.

The ages of Kavya and Karthik are 11 years and 14 years respectively. In how many years will the product of their ages will be 304 ?

The ages of Rahul and Haroon are in the rati 5:7.Four years later the sum of their ages will be 56 years.What are their present ages?

The sum of the reciprocals of Rehman's ages , (in years) 3 years ago and 5 years from now is 1/3 . Find his present age .

The age of Hari and Harry are in the ratio 5:7.Four years from now the ratio of their ages will be 3:4.Find their present ages.

Sum of the ages of a father and the son is 40 years. If father's age is three times that of his son, then find their respective ages.

When Rupa was born, her father was 25 years old. Form an equation and draw a graph for this data. From the graph find (i) The age of the father when Rupa is 25 years old. (ii) Rupa’s age when her father is 40 years old.