Capacitor with dielectric

A dielectric of thickness 5cm and dielectric constant 10 is introduced between the plates of a parallel plate capacitor having plate area 500 sq. cm and separation between the plates 10cm. The capacitance of the capacitor with dielectric slab is (epsi_(0) = 8.8 xx 10^(-12)C^(2)//N-m^(2))

Dielectrics, Capacitors with Dielectrics and Capacitor in a Circuit

Dielectrics, Capacitors with Dielectrics and Capacitor in a Circuit

Capacitors with Dielectric |Questions

The natural frequency of an LC - circuit is 1,25,000 cycles per second. Then the capacitor C is replaced by another capacitor with a dielectric medium of dielectric contant k. In this case, the frequency decreases by 25 kHz. The value of k is

A parallel plate capacitor with a dielectric slab with dielectric constant k= 3 filling the space between the plates is charged to potential V and isolated. Then the dielectric slab is drawn out and another dielectric slab of equal thickness but dielectric constant k'= 2 is introduced between the plates. The ratio of the energy stored in the capacitor later to that initially is:

A capacitor of capacitance C is connected to a battery of V volts. A dielectric k=(7)/(3) is introduced betwene the plates of the capacitor when battery is connected.The ratio of energies stored in the capacitor without dielectric and with dielectric..

parallel plate capacitor is filled by a dielectric whose dielectric constant varies with the applies voltage (V) as K = 2V. A similar capacitor with no dielectric is charged to V_(0)=78 volt.It is then connected to the uncharged capacitor with the dielectric.Find the final voltage on the capacitors

A parallel palte capacitor is filled by a dielectric whose relative permittively varies with the applied voltage (U) as epsilon = alpha U where alpha = 2V^(-1) . A similar capacitor with no dielectric is charged to U_(0) = 78V . It is then is connected to the uncharged capacitor with the dielectric. Find the final voltage on the capacitors.