Home
Class 12
PHYSICS
Calculate the half life and mean life of...

Calculate the half life and mean life of Radium -226 of activity 1Ci, Given the mass of Radium - 226 is 1 gram and 226 gram of radium consists of `6.023xx10^23` atoms.

Text Solution

Verified by Experts

Activity of 1 gram of radium is `A=3.7xx10^10` distingration per second [i.e., `1Ci=3.7xx10^10` disintegration per second]
No. of atoms in 1 gram of radium is
`N=(6.023xx10^23)/226=2.665xx10^21`
Using `A=lambdaN`
`lambda=A/N=(3.7xx10^10)/(2.665xx10^21)=1.388xx10^(-11)` per second
Half - life of radium is
`T=0.693/lambda=0.693/(1.388xx10^(-11))`
`T=0.499xx10^11` second
`=4.99xx10^10` second
Mean - Life , `tau=1/lambda=1/(1.388xx10^(-11))`
`=0.720xx10^11` second
`tau=7.20xx10^10` second.
Promotional Banner

Topper's Solved these Questions

  • SUPPLEMENTARY EXAM QUESTION PAPER JULY -2015

    SUNSTAR PUBLICATION|Exercise PART-D|11 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2014

    SUNSTAR PUBLICATION|Exercise PART-D (VI. Answer any three of the following questions.) |5 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER JUNE-2019

    SUNSTAR PUBLICATION|Exercise Part-C|18 Videos

Similar Questions

Explore conceptually related problems

Calculate the half-life period of a first order reaction, if the rate constant of the reaction is 6.93 times 10^(-3)S^(-1) .

Determine the mass of Na^(22) which has an activity of 5mCi. Half life of NA^(22) is 2.6 years. Avogadro number =6.023xx10^(23) atoms.

Calculate the force of gravitation between the earth and the sun, given that the mass of the earth = 6 xx 10^(24) kg and of the sun = 2 xx 10^(30) kg. The average distance between the two is 1.5 xx 10^(11) m.

The half life of radium is 1600 years. The number of undecayed atoms of radium after 4800 years will be :

The half life of ""_(38) Sr^(90) isotope is 28 years. What is the rate of disintegration of 15 mg of this isotope? (Given Avogadro No =6.023 xx 10^(23) )

The number of atoms in 0.1 mol of a triatomic gas is : (N_A = 6.02 xx 10^23 "mol"^(-1) )

CsBr crystallzes in a body centred cubgic lattice . The unit cell length is 436.6 pm. Given that the atomic mass of Cr= 133 and that of Br = 80 amu and Avogadro number being 6.02 xx 10 ^(23) mol ^(-1). The density of CsBr is

A radioactive element has a half life of 2.5 hours. In 10 hours 1 gram of radioactive material is reduced to