Two cells of emf 2V and 4V and internal resistance `1Omega` and `2Omega` respectively are connected in parallel so as to send the current in the same direction through an external resistance of `10Omega`. Find the potential difference across `10Omega` resistor.

Explanation

`r_(2) = 2Omega`
Applying KVL to mesh `E_(1)ABE_(1) " Equation" (1) rArr`
`1I_(1) + 10( I_(1) + I_(2)) = 2" " 1I_(1) + 10(0.75) =2`
`1I_(1) 10I_(2) = 2 to (1)" "1I_(1) = -7.5`
APplying KVL to mesh `E_(2)ABE_(2)" "11I_(1) = -5.5`
`2I_(2) + 10(I_(1) + I_(2)) = 4" "I_(1) = -0.5A`
`10I_(1) + 10I_(2) = 2" ""Potential drop across " 10Omega`
`11I_(1) + 10I_(2) = 2" "V = (I_(1) + I_(2))R`
`10I_(1) + 12I_(2) = 4" " = (-0.5 + 0.75)10`
`x^(ly)` eqn (1) by 10 and eqn (2) by 11 `" " = 0.25 xx 10`
`110I_(1) + 100I_(2) = 20 " " V = 2.5V`
`11OI_(1) + 132I_(2) = 44 " "`
`110I_(1) + 132I_(2) = 44`
`((-)(-)(-))/(-32I_(2) = -24)`
`I_(2) = (24)/(32)`
`I_(2) -0.75A`