Home
Class 12
CHEMISTRY
The rate constant of a first order react...

The rate constant of a first order reaction is `1.15 xx 10^(-3)s^(-1)`. Calculate its half life period `(t1//2)`.

Text Solution

Verified by Experts

Given `K=1.15xx10^(-3)S^(-1)`
The overall cell reaction `2H_(2(g))+O_(2(g))rarr2H_(2)O_((l))`
`t_(1//2)=(0.693)/(k)=(0.693)/(1.15xx10^(-3)s^(-1))=602.6s`
Promotional Banner

Topper's Solved these Questions

  • SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2018

    SUNSTAR PUBLICATION|Exercise PART - C|11 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2018

    SUNSTAR PUBLICATION|Exercise PART - D|28 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2018

    SUNSTAR PUBLICATION|Exercise PART - D|28 Videos
  • K-CET-CHEMISTRY-2019

    SUNSTAR PUBLICATION|Exercise Question|60 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2015

    SUNSTAR PUBLICATION|Exercise PART - D|30 Videos

Similar Questions

Explore conceptually related problems

Rate constant of a first order reaction is 6.93 xx 10^(-3) mi n^(-1) . Calculate the half-life period.

Rate constant of a first order reaction is 0.45 sec^(-1) , calculate its half life.

The rate constant of a certain first order reaction is 200S^(-1) . What is its half life period ?

If k for a first order reaction is 5.48 xx 10 ^(-14) s ^(-1), its two third life is :

Rate constant k for a first order reactions has been found to be 2.54 xx 10^(-3) sec^(-1) . Calculate its 3//4^(th) life. (log 4 = 0.6020)

Rate constant for a reaction is 1.85 xx 10^(2)s^(-1) . Give the order of reaction.

The rate constant for a fist order reaction is k = 7xx10^(-4)s^(-1) .The time taken for the reactant to be reduced to 1/2 of the initial concentration is :