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25 cm^(3) of oxalic acid completely neut...

`25 cm^(3)` of oxalic acid completely neutralised 0.064 g of sodium hydroxide. Molarity of the oxalic acid solution is

A

`0.064`

B

`0.045`

C

`0.015`

D

`0.032`

Text Solution

Verified by Experts

The correct Answer is:
D
Oxalic acid
` (25 xx N)/(1000)= (0.064)/(40)`
`N = ( 0.064 xx 1000)/(40 xx 25) = 0.064 " " :. "Molarity " = (0.064)/(2) = 0.032`
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