5.5 mg of nitrogen gas dissolves in 180 g of water at 273 K and one atm pressure due to nitrogen gas. The mole fraction of nitrogen in 180 g of water at 5 atm nitrogen pressure is approximately

Options

A. `1 xx 10^(-6)`
B. `1 xx 10^(-5)`
C. `1 xx 10^(-3)`
D. `1 xx 10^(-4)`

Answer

D

Explanation

5.5 mg in `180g to 1 ` atm
`:.` 5 atm pressure requires `5.5 mg xx 5 = 27.5` mg of `N_2`
`:.` Mole fraction of `N_2 = ((27.5 xx 10^(-3))/(28))/((180)/(18))=(10^(-3))/(10) = 1 xx 10^(-4)`