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50 cm^(3) of 0.04 M K2Cr2O7 in acidic me...

`50 cm^(3)` of 0.04 M `K_2Cr_2O_7` in acidic medium oxidizes a sample of `H_2S` gas to sulphur. Volume of 0.03 `M KMnO_4` required to oxidize the same amount of `H_2S` gas to sulphur, in acidic medium is

A

`60 cm^(3)`

B

`80 cm^(3)`

C

`90cm^(3)`

D

`120 cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`0.04M K_2Cr_2O_7 = 0.24 N K_2Cr_2O_7`
`0.03 M KMnO_4 = 0.15 N KMn_4`
`0.24 xx 50 = 0.15 xx V_2`
`V_2 = (0.24 xx 50)/(0.15) = 80 ml`
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