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I mol of NaCl is doped with 10^(-5) mole...

I mol of NaCl is doped with `10^(-5)` mole of `SrCl_(2)` .The number of cationic vacancies in the crystal lattice will be

A

`6.022xx10^(15)`

B

`6.022xx10^(18)`

C

`12.044xx10^(20)`

D

`6.022xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
B
`6.022xx108`
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