Two particle A and B are in motion. If the wavelength associated with 'A' is 33.33 nm, the wavelength associated with 'B' whose momentum is `1//3^(rd)` of 'A' is

Options

A. `2.5xx10^(-5)m`
B. `1.0xx10^(-8)m`
C. `1.0xx10^(-7)m`
D. `1.25xx10^(-7)m`

Answer

C

Explanation

`(lambda_(B))/(lambda_(A))=(P_(A))/(P_(B))implies(lambda_(B))/(33.33 nm)=(P)/((1)/(3)P)implieslambda_(B)=3xx3.33.33 nm=100nm=1xx10^(-7)M`