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If Aniline is treated with 1:1 mixture o...

If Aniline is treated with 1:1 mixture of con `HNO_(3)` and con. `H_(2)SO_(4)`,p-nitroaniline and mnitroaniline are formed nearly in equal amounts.This is due to

A

protonation of -`NH_(2)` which causes deactivation of benzene ring

B

m-directing property of -`NH_(2)` group

C

isomerisation of some p-nitoaniline into m-nitroniline

D

m and p directing property of -`NH_(2)` group

Text Solution

Verified by Experts

The correct Answer is:
A
`NH_(2)` group get protonated to `-NH_(3)` ion which is a meta directing group
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