Addition of excess of `AgNO_(3)` to an aqueous solution oof 1 mole of `PdCl_(4).4NH_(3)` gives 2 moles of AgCl.The conductivity of this solution corresponds to

Options

A. 1:3 electrolyte
B. 1:1 electrolyte
C. 1:4 electrolyte
D. 1:2 electrolyte

Answer

D

Explanation

`[Pd(NH_(3))_(4)]^(2)to[Pd(NH_(3)_(4))]^(2+)+2Cl^(-)`
1:2 electrolyte