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The CHEical equation for the manufacture...

The CHEical equation for the manufacture of ammonia is `N_2(g)+3H_2(g) to 2NH_3(g)`
Calculate the amount of `H_2` required to react with 28 g of `N_2`, completely.
[Hint Molecular mass of `N_2 = 28`, `H_2 =2`]

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The correct Answer is:
28 g `N_2` requires 3 mol `H_2` 3 mol `H_2` = `3times2=6g`
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