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Prove that chords of the same length in ...

Prove that chords of the same length in a circle are at the same distance from the center.

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Prove that chords of the same length in a circle are at the same distance from the centre.

In the figure 0 is the center of the circle. AB and PQ are two chords at equal distance from the center. A B=12 cm, OC=8 cm is the perpendicular distance from center to AB a) What is the length of PQ? b) Calculate the radius of the circle.

Circle with radius 13 cm is drawn. If AB and CD are two parallel chords of length 24cm and 10cm respectively on the same side of the center, find the distance between them.

If the arcs of the same length in two circles subtend angles 60^@ and 90^@ at their centres . Find the ratio of radii.

From a point P,the length of the tangent to a circle is 24cm and distance of P from the centre is 25cm.Find radius.

In a circle of radius 5 cm two parallel chords of lengths 6cm and 8 cm are drawn on either sides of a diam¬eter. What is the distance between them? If parallel chords of these lengths are drawn on the same side of a diameter what would be the distance between them.

Cálculate the radius of the circle in which a tangent of length '12 cm' is drawn from a point at the distance '13 cm' from the center. Draw rough figure. Use Pythagoros theorem.

In a circle of radius 25 centimetres, the lengths of two parallel chord's are 30cm and 40 cm. If the chords are on the same side of the diameter, what is the distance between? If the chords are on either of the diameter, what is the distance between them?

ln a circle of radius 13 centimetres two parallel chords of lengths 10 cm and 24 are drawn on the same side of the diameter, what would be the distance between them?