A car come to rest when brake was applied for 4s to get a retardation of `3m / s^2` .Calculate how far the car would have travelled after applying the brake.

An object starting from rest travels with a uniform acceleration of 5 m / s^2 . Calculate the velocity and distance travelled after 1 minute?

The driver of a car stops his car by applying brakes to produce a uniform retardation of 8 m//s^2 , the initial speed of the car is 72 kmph.Calculate the stopping distance of the car.

A car travels with a speed of 25 m//s for 2 minutes and then with 20 m//s for 1 minute.Calculate the total distance travelled by the car.

An object starting from rest travels with an acceleration of 5 m / s^2 . What will be its velocity after 3s?

m_1 and m_2 are the masses of two bodies. When a force of 5 N is applied on each body, m_1 gets an acceleration of 10 m//s^2 and m_2 , 20 m//s^2 . If the two bodies are tied together and the same force is applied, find the acceleration of the combined system.

Two cars A and B travelling with speed 20m/s and 10m/s respectively applied brakes, so that A comes to rest in 15 second and B in 7.5s. From the graph determine which of the two cars travelled further after brakes were applied and by how much distance it travelled?

Two cars A and B travel from the same point and in the same direction. A is travelling at a speed of 30 k(m) / hour and B at a speed of 40 (km) / hour . After 4 hours, what is the distance between the cars? How far the cars would be if they travelled in opposite direction?