Home
Class 12
PHYSICS
A 10 m long wire of resistance 20 Omega ...

A 10 m long wire of resistance `20 Omega` is connected in series with a battery of e.m.f. 3V (negligible iuternal resistance) and a resistance of `10 Omega`. Find the potential gradient along the wire.

A

`3V//m`

B

`0.2V//m`

C

`0.1V//m`

D

`0.3V//m`.

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A potentiometer wire has a resistance of 20 Omega and length 10 m. It is connected in series with a battery of emf 2.5 V and negligible internal resistance, and an external resistance of 5 Omega . Fall of potential in mV per metre is

A wire having length 2.0 m diameter 1.0 mm and resistivity 1.963 xx 10^(-8) Ω m is connected in series with a battery of emf 3V and internal resistance I Ω . Calculate the resistance of the wire and current in the circuit.

A wire of resistance 1Omega is elongated by 10%. The resistance of the elongated wire is

Two heating coils of resistance 10Omega and 20Omega are connected in parallel and connected to a battery of emf 12V and internal resistance 1Omega . The power consumed by them are in the ratio

A uniform wire of resistance 24 Omega is bent in form of a regular hexagon ABCDEF . A cell of e.m.f. 4 volt having negligible internal resistance is connected across the side AB of the hexagon. The field at its centre will be

A battery of e.m.f. 12V and internal resistance 2Omega is connected in series with a tangent galvanometer of resistance 4Omega . The deflection is 60^@ when the plane of the coil is along the magnetic meridian. To get a deflection of 30^@ , the resistance to be connected in series with the tangent, galvanometer is :

(a) Three resistors of resistance 2Omega,3Omega and 4Omega are combined in series. What is the total resistance of the combination ? (b) It this combination is connected to a battery of emf 10 V and negligible internal resistance, obtain the potential drop across each resistor.

Two resistors of resistances 2 Omega and 6 Omega are connected in parallel. This combination is then connected to a battery of emf 2 V and internal resistance 0.5 Omega . What is the current flowing through the battery ?