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An electric bulb is designed to draw pow...

An electric bulb is designed to draw power `P_0` at voltage `V_0`. If the voltage is V it draws a power P. Then

A

`P=(V/V_0)^2 P_0`

B

`P=(V_0/V)^2 P_0`

C

`P=(V_0/V)P_0`

D

`P=V_0/V P_0`.

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