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A proton moving with a velocity of 2 xx ...

A proton moving with a velocity of `2 xx 10^6 ms^-1` describes a circle of radius `R` in a magnetic field. The speed of an `alpha`-particle to describe a circle of same radius in the same magnetic field is

A

`1 xx 10^6 m s^-1`

B

`2 xx 10^6 m s^-1`

C

`4 xx 10^6 m s^-1`

D

`8 xx 10^6 m s^-1`.

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Knowledge Check

  • If an electron describes half a revolution in a circle of radis r, in a magnetic field B, the energy acquired by it is :

    A
    zero
    B
    `1//2 mv^(2)`
    C
    `(1)/(4) mv^(2)`
    D
    `pi r Be V`

  • A charged particle with a velocity 2 xx 10^(3) ms^(-1) passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5 T. The magnitude of electric field will be

    A
    `1 . 5 xx 10^(3) NC^(-1)`
    B
    `2 xx 10^(3) NC^(-1)`
    C
    `3 xx 10^(3) NC ^(-1)`
    D
    `1 . 33 xx 10^(3) NC^(-1)`

  • A charged particle with a velocity 2xx10^(3)ms^(-1) passes undeflected through electric field and magnetic fields in mutually perpendicular directions. The magnetic field is 1.5T. The magnitude of electric field will be:

    A
    `1.5xx10^(3)NC^(-1)`
    B
    `2xx10^(3)NC^(-1)`
    C
    `3xx10^(3)NC^(-1)`
    D
    `1.33xx10^(3)NC^(-1)`

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