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A current I = I0 sin (omega t + pi//2) f...

A current `I = I_0 sin (omega t + pi//2)` flows in a circuit when an alternating voltage `E = E_0 sin omegat` is applied. The power consumed in the circuit is

A

`(E_0I_0)/sqrt2`

B

`E_0I_0`

C

zero

D

`(E_0I_0)/2`.

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