Home
Class 12
PHYSICS
In Young’s experiment, the ratio of maxi...

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is `4 : 1`. The amplitudes of the coherent sources are in the ratio

A

`4 : 1`

B

`3 : 1`

C

`2 : 1`

D

`1 : 1`.

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

In an interference experiment, intensity ratio at bright to dark fringe is 9 : 1 , Amplitudes of interfering waves are in the ratio

In Young’s double slit experiment on interference, the ratio of the intensities of a bright band and a dark band is 16 : 1. The ratio of the amplitudes of the interfering waves is

The ratio of the maximum to the minimum wavelengths in Balmer series of H spectrum is

The amplitude of the light waves emerging from the two slits in Youngs experiment is in the ratio of 2 : 3. The intensity of the minimum to that of the consecutive maximum will be in the ratio of:

The intensity of the light emerging from the two slits in Youngs experiment is in the ratio 1 to 4. The intensity of the minimum to the consecutive maximum will be in the ratio of :

In Young’s experiment, the interference pattern is found to have an intensity ratio between the bright and dark fringes as 9. What is the ratio of intensity of two interfering waves ?

In an interference pattern the ratio of the intensity of light at the bright fringe to that at the dark fringe is 9 : 1 . Then the ratio of the amplitudes of the two interfering waves.

In Young’s double slit experiment, the central bright fringe can be identified

In Young’s double slit experiment, the distance of screen is increased 4 times and distance between two coherent sources is reduced to half. The fringe width will