The wavelength of the light used in Young’s double slit experiment, is `lambda`. The intensity at a point on the screen where the path difference is `lambda/6` is `I`. If `I_0` denotes the maximum intensity, then the ratio of `I` and `I_0` is................

Options

A. 0.75
B. 0.707
C. 0.5
D. 0.866.