Home
Class 12
PHYSICS
A photon of energy 4 eV is incident on a...

A photon of energy 4 eV is incident on a metal surface whose work function is 2 eV. The minimum reverse potential to be applied for stopping the emission of electrons is

A

8 V

B

6 V

C

4 V

D

2 V.

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A photon of frequency 1.5xx10^(15) Hz is incident on a metal surface of work function 1.672 eV. Calculate the stopping potential.

Light of wavelength 4700Å is incident on a metal plate whose work function is 2 eV. Then maximum kinetic energy of the emitted photoelectron would be

The light photons of energy 1.5 eV and 2.5 eV are incident on a metallic surface of work function 0.5 eV, the ratio of the maximum kinetic energy of the photoelectrons is

Light of wavelength lambda = 400 nm is incident on a photosensitive metal whose work function is 2 eV. The maximum kinetic energy of photo electrons emitted will be

A photon of energy 10 eV is incident on a metal surface of threshold frequency 1.6 xx 10^15 Hz . The kinetic energy of the photoelectron (in eV) is (assume h = 6 x 10^-34 )

A photon of energy 8 eV is incident on a metal surface of threshold frequency 1.6 xx 10^15 Hz . The K.E. of the photoelectrons emitted is (in eV). Take h as 6 xx 10^-34 J s .

Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, successively illuminate a metallic surface whose work function is 0.5 eV. Ratio of maximum speeds of emitted electrons will be