Home
Class 12
PHYSICS
When light of wavelength 300 nm falls on...

When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

A

`4 : 1`

B

`1 : 4`

C

`1 : 2`

D

`2 : 1`.

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

Yellow light has wavelength 600 nm in air. What is the wavelength of yellow light in water. Refractive index of water = 4/3 .

Light of certain wavelength and intensity ejects photoelectrons from a metal plate. Then this beam is replaced by another beam of smaller wavelength and smaller intensity. As a result

A singled slit of width a is illuminated by violet light of wavelength 400 nm and the width of diffraction pattern is measured as y . When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm, the width of the diffraction pattern is

Light of wavelength 4700Å is incident on a metal plate whose work function is 2 eV. Then maximum kinetic energy of the emitted photoelectron would be

Light of wavelength lambda = 400 nm is incident on a photosensitive metal whose work function is 2 eV. The maximum kinetic energy of photo electrons emitted will be

A monochromatic source emitting light of wavelength 600 nm has a power output of 66 W. Calculate the number of photons emitted by this source in 2 minutes.

The photo electric threshold for a metal surface is 5800 Å. Calculate the kinetic energy of a photoelectron, when a light of wavelength 4500 Å is incident on the metal surface.