Home
Class 12
PHYSICS
An electron of mass m(e) and a proton of...

An electron of mass `m_(e)` and a proton of mass `m_(p)` are moving with the same speed.The ration of their de-Broglie's wavelengths `(lambda_(e))/(lambda_(p))` is

A

918

B

`1/1836`

C

1836

D

1

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

An alpha -particle and a deutron are moving with the same kinetic energy. The ratio of their de Broglie wavelengths is

An alpha -particle and deutron are moving with the same momenta. What will be the ratio of their de Broglie wavelengths ?

A particle of mass M at rest decays into two masses m_(1) and m_2 with non zero velocities. The ratio of de-Broglie wavelengths of the particles (lamda_(1))/(lamda_(2)) is

An electron (mass m_e ) and a proton (mass m_p ) are accelerated through the same potential, then lambda_e//lambda_p =

A proton and an alpha particle are accelerated through the same potential difference V. The ratio of their de Broglie wavelengths is

An electron, an alpha- particle, and a proton have the same kinetic energy. Which of these particles has the shortest de Broglie wavelength?

An electron of mass m_e and a proton of mass m_p are injected into a uniform magnetic field at right angles to the direction of the field, with equal velocity. The ratio of the radii of their orbits r_e//r_p is equal to