Home
Class 12
PHYSICS
The forbidden energy gap in Ge in 0.72 e...

The forbidden energy gap in Ge in 0.72 eV Given, `hc=12400" eV"-Å` The maximum wavelength of radiation that will generate electron hole pair is

A

`1722 overset@A`

B

`17222 overset@A`

C

`172.2 overset@A`

D

`172220 overset@A`.

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV.

when a certain energy is applied to an hydrogen atom, an electron jumps from n =1 to n = 3 state. Find (i) the energy absorbed by the electron. (ii) wavelength of radiation emitted when the electron jump back to its initial state. ( Energy of electron in first orbit = - 13.6 eV , Planck's constant = 6.6225 xx10^(-34) Js, Charge on electron = 1.6 xx10^(-19) C, speed of light in vacuum = 3xx10^(8)ms^(-1)

The forbidden gap within germanium and silicon are 0.7 eV and 1.1 eV respectively. It implies that

In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å (a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at infinite separation of the electron from proton. (b) What is the minimum work required to free the electron, given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in (a)? (c) What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 Å separation?

The ground state energy of hydrogen atom is - 13.6 eV. If an electron makes a transition from an energy level - 0.85 eV to -3.4 eV, calculate the wavelength of the spectral line emitted. To which series of hydrogen spectrum does this wavelength belong?