Home
Class 12
PHYSICS
Two springs having their force constants...

Two springs having their force constants `k_1` and `k_2` are stretched through same distance. Ratio of their energies `P.E_1`, and `P.E_2` is

A

`sqrtk_1 : sqrtk_2`

B

`k_2 : k_1`

C

`k_1:k_2`

D

`k_2^2:k_1^2`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

If two springs S, and S, of force constants k, and ky, respectively, are stretched by the same force, it is found that more work is done on spring S, than on spring S. Statement 1: If stretched by the same amount, work done on S, will be more than that on S. Statement 2: k_1 lt k_2

Two reactions A rarr Products and Brarr products have rate constants k_(A) and k_(B) respectively at temperature T and activation energies E_(A) and E_(B) respectively . If k_(A) gt K_(B) and E_(A) lt E_(B) and assuming that A for both the reactions is same then :

The P.E. of a spring is E_(P) when is stretched through 1cm. When stretched through 2 cm, ils P.E. is

If T_(1) and T_(2) are the time of oscillations for two springs of constants k_(1) and k_(2) connected to the mass m individually then calculate the time period of oscillations when both the spring are connected to the same mass and subjected to oscillations.