Home
Class 12
PHYSICS
The null point in a potentiometer with a...

The null point in a potentiometer with a cell of e.m.f. `xi` is obtained at a distance `l` on the wire. Then :

A

`xi prop l`

B

`xi prop l^2`

C

`xi prop 1/l`

D

`xi prop 1/l^2`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The balance point of a potentiometer with two cells in series is at l= 250 cm. And if one cell is reversed the balance point is at l_1 = 150 cm. The ratio of emfs of the two cells is

What is the unit of e.m.f?

Figure shows a long potentiometer wire AB having a constant potential gradient. The null points for the two primary cells of emfs epsi _(1) and epsi _(2) connected in the manner shown are obtained at a distance of l _(1) = 120 cm and l _(2) = 300 cm from the end A. Determine (i) epsi _(1) //epsi _(2) and (ii) position of null point for the cell epsi _(1) only.

In a potentiometer of 10 wires, the balance point is obtained on the 6th wire. To shift the balance point to 8th wire, we should :

In a potentiometer arrangement, a cell of emf 1.25V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0cm, what is the emf of the second cell ?

In a potentiometer experiment of a cell of emf 1.25 V gives balancing length of 30 cm. If the cell is replaced by another cell, balancing length is found to be 40 cm. What is the emf of second cell ?

In a potentiometer experiment, two cells of emf E_1 and E_2 are used in series in the secondary circuit. The balancing length is found to be 58 cm. If the polarity of E_2 is reversed, the balancing length becomes 29 cm. The ratio E_1//E_2 of the emfs of two cells is :