If y=ax^(n+1) + bx^(-n) , then x^2(d^2y)...

If `y=ax^(n+1) + bx^(-n)` , then `x^2(d^2y)/(dx^2)` is equal to

A

`n(n-1)y`

B

`n(n+1)y`

C

`ny`

D

`n^2y`.

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