A circle has radius 3 units and its cent...

A circle has radius 3 units and its centre lies on the line `y =x-1.` Then the equation of this circel if it passes through point `(7,3)` is

A

`x^2+y^2-8x-6y+16=0`

B

`x^2+y^2+8x+6y+16=0`

C

`x^2+y^2-8x-6y-16=0`

D

`x^2+y^2+8x-6y-16=0`

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