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The equation of tangents to the circle x...

The equation of tangents to the circle `x^2+y^2-22x-4y+25=0` which are perpendicularr to the line `5x+12y+8=0` are

A

`12x-5y+8=0`,`12x-5y=252`

B

`12x-5y=0`,`12x-5y=252`

C

`12x-5y-8=0`,`12x-5y+252=0`

D

`12x-5y+25=0`,`12x-5y+16=0`

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