Home
Class 11
MATHS
The equation of the circle having x -y -...

The equation of the circle having `x -y -2 =0 and x -y + 2=0` as two tangents and `x + y =0` as a diameter is

A

`x^2+y^2+2x-2y+1=0`

B

`x^2+y^2-2x+2y-1=0`

C

`x^2+y^2=2`

D

`x^2+y^2=1`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the the circle having x - y - 2 = 0 and x - y + 2 = 0 as two tangents , and x + y = 0 as a diameter is

Find the equation of the circle if the equations of its two diameters are 2x+y=6 and 3x+2y=4 when radius is 9 units.

Find the equation of the circle concentric with the circle x^2 + y^2 - 4x - 6y - 3 = 0 and which touches the y axis

The equation to the tangent to the circle x^2+y^2-x+3y=10 at (-2,1) is

The equations of the tangents to the circle x^2+y^2=a^2 parallel to the line sqrt3x+y+3=0 are

The equation of a diameter of circle x ^(2) + y^(2)-6x + 2y =0, passing through origin is

The equation of the tangents to the circle x^2+y^2-20x+12y+11=0 having slope -2 are

Find the equation of a tangent to the circle x^2+y^2-3x+2y=0 at origin.