A person consumers 300 ml `O_2` by lungs. The `O_2` carrying capacity of his artery and vein are 20 ml and 15 ml respectively. Determine the cardiac output (minute volume) of that person.

Volumes of N_(2) and O_(2) in any gas mixture are 80% and 20T respectively. Determine the average vapour density of the gas mixture.

At 300K , the partial pressures of N_2O_4 (g) and NO_2 (g) in an equilibrium mixture of the reaction: N_2O_4(g)

Tidal Volume and Expiratory Reserve Volume an athlete is 500 mL and 1000 mL respectively. What will be his Expiratory Capacity if the Residual Volume is 1200 mL?

A definite volume of H_2O_2 undergoing decomposition required 22.8 mL of standard KMn O_4 solution for titration. After 10 and 20 min, the volume of permanganate required were 13.8 and 8.25 mL respectively. Find out the order of the reaction.

The strengths of three H_(2)O_(2) solutions are 10,15 and 20 volume respectively. 0.5L of each of these solutions are mixed and equal amount of water is added to it. Determine the volume strength of the mixed solution.

What would be the cardiac output of a person having 72 heart beats per minute and a stroke volume of 50 mL ?

Determine the volume strength of 1.5 (N) H_(2)O_(2) .

The respective mole fractions of N_(2) and O_(2) is dry air are 0.78 and 0.21 gt if the atmospheric presure and temperature are 740 torr and 20^(@)C respectively, then what will be the mass of N_(2) and O_(2) present in a room of volume of 3000ft^(3) ? (Assuming the relative humidity of air as zero)

At 300 K and 1 atm, 15 mL of gaseous hydrocarbon requires 375 mL air containing 20% O_(2) by volume for complete combustion. After combustion the gases occupy 330 mL. assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is-

60 mL of a mixture of CO and H_(2) , mixed with 40 mL of O_(2) , are subjected to explosion in a eudiometer tube. On cooling the gas mixture after the end of the reaction, the volume is reduced to 30 mL. determine the compostion of the gas mixture initially taken. [All volumes are measured at the same temperature and pressure].