Explain why `Cr^(2+)` behaves reducing while `Mn^(3+)` oxidising through both are havign `d^9` configuration. What is interstetial compound?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Explain why Mn^(2+) is more stable than Mn^(3+) ?

Explain why 2d and 3f orbitals do not exist?

Explain why [Ti(H_2O)_6]^(3-) is coloured while [Sc(H_2O)_6]^(3+) is colourless.

With the same d-orbital configuration, Cr^(2+) is a reducing agent while Mn^(3+) is an oxidising agent.Explain.

Explain why the Sn (II) salts are used as reducing agents while Pb (IV) salts are used as oxidising agents.

Why are Mn^(2+) compounds more stable than Fe^(2+) towards oxidation to their + 3 state ?

SO_(2) possess both oxidising and reducing property, while SO_(3) possess only oxidising property. Explain.

(1) MnO_(4)^(-)(aq)+8H^(+)(aq)+5e rarr Mn^(2+)(aq)+4H_(2)O(l), E^(@)=+1.51V (2) Cr_(2)O_7)^(2-)(aq)+14H^(+)+6e rarr 2Cr^(3+)(aq)+7H_(2)O(l), E^(@)=+1.38V (3) Cl_(2)(g)+2e rarr 2Cl^(-)(aq), E^(@)=+1.40V KMnO_(4) and K_(2)Cr_(2)O_(7) both are well known oxidising agent and used in quantitative analysis. If a solution of a reducing agent contains HCl, which one between these two should not be used as an oxidising agent?

What is the atomic number of the element with M^(2+) ion having electronic configuration [Ar]3d^(8) -