A solution of `2.44xx10^-3` kg of a nonelectrolyte solute dissolved in 0.075 kg of water boiled at `100.413^@C`. Calculate the molecular mass of the solute. `K_b` for water = `0.52 K kg mol^-1`

A solution contains 5.6 gm of glucose in 1000 gm of water. Calculate the boiling point of the solution. ( k_b for water = 0.52 K kg mol^-1 )

The elevation of boiling poin is 0.70K when 12.5gm of a non electrolyte gets dissolved in 175 gm of water. Cacluate mole mass of the substance K_b =52K Kg mol^(-1)

The boiling point of a solution containing 1.5 g of dichlorobenzene in 100 g of benzene was higher by 0.268^@C . Calculate the molar mass of dichlorobenzene. K_b forbenzene = 2.42 K kg mol^-1

What do you mean by molal ebuloscopic constant K_b for water 0.515^@C kg mol^-1 .

A solution containing 6 gm of a solute dissolved in 250 ml of water gave an osmotic pressure of 4.5 atmosphere at 27^(@)C . Calculate the boiling point of the solution. The molal elevation constant for water is 0.52

A solution containing 2.5 g of a non-volatile solute in 100 gm of benzene boiled at a temperature 0.42K higher than at the pure solvent boiled. What is the molecular weight of the solute? The molal elevation constant of benzene is "2.67 K kg mol"^(-1) .

Calculate the boiling point of 1(M) KCI soln density 1.04 gm/cc (Kb =0.52K. Kg. mol^(-1)

20 g of a solid solute is dissolved in 180 g of water. At 100^(@)C the vapour pressure of the solution becomes 740 mmHg. Calculate relative molecular mass of the solute. (No association/dissociation of the solute takes place )

1.26 gm of a protine dissolved in 200 cc aqueous solution shows an osmotic pressure of 2.57xx10^-3 bar at 300K. Calculate the molecular weight of the protine.

Dry air was passed successively through a solution of 5 gm of solute dissolved in 80.0 gm of water and through pure water. The loss in weight of the solution was 2.5 gm and that of the pure solvent was 0.04 gm. What is the molecular weight of the solute?