A solution contains 5.6 gm of glucose in 1000 gm of water. Calculate the boiling point of the solution. (`k_b` for water = `0.52 K kg mol^-1`)

Calculate the boiling point of 1(M) KCI soln density 1.04 gm/cc (Kb =0.52K. Kg. mol^(-1)

A solution of 2.44xx10^-3 kg of a nonelectrolyte solute dissolved in 0.075 kg of water boiled at 100.413^@C . Calculate the molecular mass of the solute. K_b for water = 0.52 K kg mol^-1

34.2 gm Sucrose (Molecular wt 342) is dissolved in 1000 gm of water. Find the freezing-point of the solution kf = 1.86 K Kg mol^-1

Dry air was passed successively through a solution of 5 gm of solute dissolved in 80.0 gm of water and through pure water. The loss in weight of the solution was 2.5 gm and that of the pure solvent was 0.04 gm. What is the molecular weight of the solute?

At 100^(@)C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If k_(b) = 0.5 , the boiling point of this solution will be -

How much heat 50 gm of water at 25^@C will take to reach boiling point?

A solution containing 6 gm of a solute dissolved in 250 ml of water gave an osmotic pressure of 4.5 atmosphere at 27^(@)C . Calculate the boiling point of the solution. The molal elevation constant for water is 0.52

At 100^@C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If K_b = 0. 52, the boiling point of this solution will be.

What is the freezing point of solution containing 3g of a non-volatile solute in 20g of water. Freezing point of pure water is 273K, K_(f) of water = 1.86 Kkg/mol. Molar mass of solute is 300 g/mol. T^(@)-T=K_(f)m

The elevation of boiling poin is 0.70K when 12.5gm of a non electrolyte gets dissolved in 175 gm of water. Cacluate mole mass of the substance K_b =52K Kg mol^(-1)