Calculate the EMF of the electrochemical cell for which the following cell reaction is given below-
`Zx(S) + ni^(2_+)(aq) rarr Zn^(+2)(aq) + Ni(S)`
Given `E_(zn^2//zn)^@ = - 0.76 V E_(Ni^(2+) // Nl) = - 0.25 V.`

Write the electrochemical cell for the overall cell reaction Zn_((s))+2AgNO_(3)rarr2Ag_((s))+Zn(NO_(3))_(2) .

Calculate DeltaG^@ in kJmol^(2+) and equilibrium constant for the following cell reaction: Zn(s)+Cu^(2+)(aq)harrCu(s)+Zn^(2+)(aq) [Give: E_(Zn^(2+)//Zn)^@=-0.76 V, E_(Cu^(2+)//Cu)^@=+0.34V,F=96500 C mol^(-1)]

The cell used in watch has the following cell reaction. Calculate E^@ & DeltaG^@ for it. Zn(s) + Ag_2O(s) + H_2O (l) rarr 2Zn^(2+) (aq) + 2Ag (s) + 2OH^- (aq) Given E^@_(Ag^+//Ag) = +0.80 V , E^@_(Zn^(2+)//Zn) = -0.76 V

Determine DeltaG^@ and the value of the equlibrium constant for the following reaction occurring in an electrochemical cell at 25^@C . Cu (s) + 2Ag^+ (aq) rarr Cu^(2+)(aq)+2Ag(s) Given that E_(Cu^(2+)//Cu)^@=0.34 V and E_(Ag^+//Ag)^@ =0.80V

Calculte the standard free energy change for the reaction occurring in a Daniell cell (E_("cell")^(@)=1.10V) . Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s)

Complete the following reactions: Zn(s) + NaOH(aq) underset( rarr)" heat "

Calculate Delta_(r)G^(@) and emf (E) that can be obtained from the following cell under the standard conditions at 25^(@)C? Zn(s)|Zn^(2+)(aq)||Sn^(2+)(aq)|Sn(s) ["Given : "E_(Zn^(2+)|Zn)^(@)=-0.76V , E_(Sn^(2+)|Sn)^(@)=-0.14V and F="96500 C.mol."^(-1)]

Determine DeltaG^(@) and the value of the equilibrium constant for the following reaction occurring in an electrochemical cell at 25^(@)C . Cu(s)+2Ag^(+)(aq)rarr Cu^(2+)(aq)+2Ag(s) Given that, E_(Cu^(2+)|Cu)^(@)=0.34V and E_(Ag^(+)|Ag)^(@)=0.80V

Calculate the E.M.F. for the cell given below Mg(S)|Mg^(2+)(0.001)(M)||Cu^(2+)(0.01M)|Cu(S) given E_(Mg^(2+)//Mg)^@ =-2.36V. E_(Cu^(2+)//Mg)^@ =+0.34V

Calculate the E.M.F. for the cell given below and identify the cathod and anode. Mg (S) | Mg^(2+) (0.001M) || CU^(2+) (0.01M) | Cu(S) E_(Mg^(2+)//Mg) = - 2.36 V and E_(Cu^(2+)//Cu) = + 0.34 V.