How much quantity of ethylene glycol is added in 200 gm water to reduce the freezing point by 0.93K? Kf=1.86K. Kg `mol^(-1)`

Ethylene glycol is used as antifreezing agent to prevent the freezing of water in car radiator in cold climate. Calculate the amount of ethylene glycol to be added to 5 kg of water to prevent it from freezing at -6^@C . Given K_f for water = 1.85 kg mol^-1 .

The temperature of a city was found tobe -9.30^@C . A car was used, whose radiator was filled with 5 L of water. What quantity of anti freezing agent ethylene glycol were added to water of radiator in order to use the car for travelling ? ( K_f of water 1.86 K kg mol^-1 )

34.2 gm Sucrose (Molecular wt 342) is dissolved in 1000 gm of water. Find the freezing-point of the solution kf = 1.86 K Kg mol^-1

50g of antifreeze (ethylene glycol) is added to 200 g water. What amount of ice will separate out at -9.3^@C ?

Calculate the amount of ice that will separate out on cooling a solution containing 50g ethylene glycol in 200g water to -9.3^@C .( k_f for water = 1.86 K kg mol^-1 )

KBr is 80% dissociated in aqueous solution. The freezing point of a 0.5 molal solution is K_f =1.86 K kg mol^-1

When 250 mg of eugenol is added to 100 g of camphor (k_f = 39.7 k molality^(-1)) , it lowered the freezing point by 0.62^@C . The molar mass of eugenol is :

k_f for water is 1.86 k kg mol^(-1) If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_2H_6O_2) must you add to get the freezing point of the solution lowered to - 2. 8^@C ?

A solution of 1.25 g of 'P' in 50g of water lowers freezing point by 0.3^@C . Molar mass of 'P' is 94. K_f(water) is 1.86 K kg mol^(-1). The degree of association of 'P' in water is [Assume dimerisation of P]

When 45 g of an unknown compound was dissolved in 500 g of water, the solution has freezing point of -0.93^(@)C (i) What is the molecular weight of compound ? (K_(f)=1.86) (ii) If empirical formula is CH_(2)O , what is the molecular formula of compound ?