Suppose the sum of the geometric series `3+6+12+`…`+1536` is 3069 Assuming that the sum contains n terms prove that `r^(n-1)=512`

Suppose the sum of the geometric series 3+6+12+ … +1536 is 3069 Find the number of terms in the series

Find the sum to n terms of the series 3+15+35+63+ cdots .

Find the sum of n terms of the series 7+77+777+..

Find the sum of n terms of the series : 5+7 +13 +31+85 + cdots .

Let A, be the sum of the first n terms of the geometric series 704 + (704)/(2) +(704)/(4) +(704)/(8)+ cdots and B_(n) , be the sum of the first n terms of the geometric series 1984 - (1984)/(2) + (1984)/(4) -(1984)/(8) + cdots If A_(n), =B_(n) , then the value of n is (where n in N).

Find the sum to n terms of the series whose n^(th) term is (2n-1)^2

Find the sum to n terms of the series: 5+11+19+29+41 .....

Find the sum to n terms of the series: 8, 88, 888 ,…..

Find the sum to n terms of this series. 1^2+3^2+5^2+……….