If p and q are the lenghts of the perpendiculars from the origin to the lines `x cos theta - y sin theta = k cos 2theta` and `x sec theta + y cosec theta = k` respectively prove that `p^2 + 4q^2= k^2`

Solve sqrt 2+sin theta=cos theta .

If p and q are respectively the perpendiculars from the origin upon the straight lines, whose equations are x sec theta + y cosec theta = a and x cos theta - y sin theta =a cos 2 theta, then 4p ^(2) + q ^(2) is equal to a) 5a^(2) b) 4a ^(2) c) 3a ^(2) d) 2a ^(2)

Find perpendicular distance from the origin of the line joining the points (cos theta, sin theta) and (cos phi, sin phi)

If p_(1)andp_(2) are respectively length of perpendiculars from the origin to the straight lines x"sec"theta+y"cosec"theta=a " " and x "cos"theta-y"sin"theta=a"cos"2theta , then 4p_(1)^(2)+p_(2)^(2) is equal to

Find (dy/dx) if x= k( theta-sin theta), y=k(1+cos theta)

Prove that sin (3theta)/(1+2cos 2theta)=sin theta .

If x=h+asec thetaandy=k+b cosec theta . Then

Find the slope of the normal to the curve x=1-a sin theta, y=b cos ^2 theta at theta=pi/2

Given that tantheta=a/b find sin2theta and cos2theta