Let `**` be a binary operation on the set Q of rational numbers as follows
`a**b=a+ab`.
Is the binary operation commutative and associative ?

Explanation

`a**(b**c)=a**(b^2+c^2)`
`=a^2+(b^2+c^2)^2`
`(a+b)+c=(a^2+b^2)+c`
`=a^2+b^2+(c^2)^2`
`=a^2+b^2+c^4`
`therefore a**(b**c)ne (a**b)**c`
`therefore **` is not associative