Find all points of discontinuity of `f` where `f` is defined by `f(x)={(2x+3,xle2),(2x-3,x>2):}`

Explanation

`f(x)={(x,ifxle1),(5, ifx>1):}}` For `xgt1,f(x)=5` which is a constant function and therefore conti nuous. Hence f(x) is continuous at x=2.