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Find dy/dx of the following y=sin^(-1)...

Find `dy/dx` of the following
`y=sin^(-1)((2x)/(1+x^2))`

Text Solution

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`y=sin^-1((2x)/(1+x^2))=2tan^-1xtherefore(dy)/(dx)=2xx1/(1+x^2)=2/(1+x^2)sin^-1((2x)/(1+x^2))=2tan^-1x`
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